by ttt2 (version ttt2 1.15)
The rewrite relation of the following TRS is considered.
| a(b(x0)) | → | x0 |
| a(c(x0)) | → | c(c(x0)) |
| b(c(x0)) | → | a(b(a(b(x0)))) |
| b#(c(x0)) | → | b#(x0) |
| b#(c(x0)) | → | a#(b(x0)) |
| b#(c(x0)) | → | b#(a(b(x0))) |
| b#(c(x0)) | → | a#(b(a(b(x0)))) |
The dependency pairs are split into 1 component.
| b#(c(x0)) | → | b#(a(b(x0))) |
| b#(c(x0)) | → | b#(x0) |
| [b#(x1)] | = | 1 · x1 + -∞ |
| [a(x1)] | = | 1 · x1 + 5 |
| [b(x1)] | = | -1 · x1 + 3 |
| [c(x1)] | = | 1 · x1 + 8 |
| a(b(x0)) | → | x0 |
| a(c(x0)) | → | c(c(x0)) |
| b(c(x0)) | → | a(b(a(b(x0)))) |
There are no pairs anymore.