YES
Termination Proof
Termination Proof
by ttt2 (version ttt2 1.15)
Input
The rewrite relation of the following TRS is considered.
| 
a(b(x0)) | 
→ | 
b(c(a(x0))) | 
| 
b(c(x0)) | 
→ | 
c(b(b(x0))) | 
| 
b(a(x0)) | 
→ | 
a(c(b(x0))) | 
Proof
1 Rule Removal
      Using the
      linear polynomial interpretation over (2 x 2)-matrices with strict dimension 1 
            over the arctic semiring over the integers
| [a(x1)] | 
 =  | 
 · 
                    x1 + 
 | 
| [b(x1)] | 
 =  | 
 · 
                    x1 + 
 | 
| [c(x1)] | 
 =  | 
 · 
                    x1 + 
 | 
          the
          rules
| 
b(c(x0)) | 
→ | 
c(b(b(x0))) | 
| 
b(a(x0)) | 
→ | 
a(c(b(x0))) | 
          remain.
        1.1 String Reversal
        Since only unary symbols occur, one can reverse all terms and obtains the TRS        
        
| 
c(b(x0)) | 
→ | 
b(b(c(x0))) | 
| 
a(b(x0)) | 
→ | 
b(c(a(x0))) | 
1.1.1 Dependency Pair Transformation
          The following set of initial dependency pairs has been identified.
          
| 
c#(b(x0)) | 
→ | 
c#(x0) | 
| 
a#(b(x0)) | 
→ | 
a#(x0) | 
| 
a#(b(x0)) | 
→ | 
c#(a(x0)) | 
1.1.1.1 Dependency Graph Processor
The dependency pairs are split into 2
        components.